“Загрузка файла PHP” Ответ

Базовый код для загрузки файлов в PHP

//This is the minimal code for an image upload for first time learners
//html portion
<!DOCTYPE html>
<html>
<head>
	<title>ImageUpload</title>
</head>
<body>
	<form action="upload.php" method="post" enctype="multipart/form-data">
		<label>Username</label>
		<input type="text" name="username">
		<br>
		<label>UploadImage</label>
		<input type="file" name='myfile'>
		<br/>
		<input type="submit" value="upload">
	</form>
</body>
</html>
  
 //php portion
  <?php
	$user=$_POST['username'];
	$image=$_FILES['myfile'];
	echo "Hello $user <br/>";
	echo "File Name<b>::</b> ".$image['name'];

	move_uploaded_file($image['tmp_name'],"photos/".$image['name']);
	//here the "photos" folder is in same folder as the upload.php, 
	//otherwise complete url has to be mentioned
	?>
bodhaditya

Загрузить файл в php

<?php
// connect to the database
$conn = mysqli_connect('localhost', 'root', '', 'file-management');

// Uploads files
if (isset($_POST['save'])) { // if save button on the form is clicked
    // name of the uploaded file
    $filename = $_FILES['myfile']['name'];

    // destination of the file on the server
    $destination = 'uploads/' . $filename;

    // get the file extension
    $extension = pathinfo($filename, PATHINFO_EXTENSION);

    // the physical file on a temporary uploads directory on the server
    $file = $_FILES['myfile']['tmp_name'];
    $size = $_FILES['myfile']['size'];

    if (!in_array($extension, ['zip', 'pdf', 'docx'])) {
        echo "You file extension must be .zip, .pdf or .docx";
    } elseif ($_FILES['myfile']['size'] > 1000000) { // file shouldn't be larger than 1Megabyte
        echo "File too large!";
    } else {
        // move the uploaded (temporary) file to the specified destination
        if (move_uploaded_file($file, $destination)) {
            $sql = "INSERT INTO files (name, size, downloads) VALUES ('$filename', $size, 0)";
            if (mysqli_query($conn, $sql)) {
                echo "File uploaded successfully";
            }
        } else {
            echo "Failed to upload file.";
        }
    }
}
Olala Victor

Загрузка файла PHP

<!DOCTYPE html>
<html>
<body>

<form action="upload.php" method="post" enctype="multipart/form-data">
  Select image to upload:
  <input type="file" name="fileToUpload" id="fileToUpload">
  <input type="submit" value="Upload Image" name="submit">
</form>

</body>
</html>
naly moslih

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