PHP чек на будний день даты
$dayofweek = date('w', strtotime($date));
$result = date('Y-m-d', strtotime(($day - $dayofweek).' day', strtotime($date)));
Fair Fish
$dayofweek = date('w', strtotime($date));
$result = date('Y-m-d', strtotime(($day - $dayofweek).' day', strtotime($date)));$firstday = date('l - d/m/Y', strtotime("this week"));
echo "First day of this week: ", $firstday;// Prints the day
echo date("l") . "<br>";
Things to be aware of when using week numbers with years.
<?php
echo date("YW", strtotime("2011-01-07")); // gives 201101
echo date("YW", strtotime("2011-12-31")); // gives 201152
echo date("YW", strtotime("2011-01-01")); // gives 201152 too
?>
BUT
<?php
echo date("oW", strtotime("2011-01-07")); // gives 201101
echo date("oW", strtotime("2011-12-31")); // gives 201152
echo date("oW", strtotime("2011-01-01")); // gives 201052 (Year is different than previous example)
?>
Reason:
Y is year from the date
o is ISO-8601 year number
W is ISO-8601 week number of year
Conclusion:
if using 'W' for the week number use 'o' for the year.
date('w'); //gets day of week as number(0=sunday,1=monday...,6=sat)
//note:returns 0 through 6 but as string so to check if monday do this:
if(date('w') == 1){
echo "its monday baby";
}$monday = strtotime('last monday', strtotime('tomorrow'));
$sunday = strtotime('+6 days', $monday);
echo "<P>". date('d-M-Y', $monday) . " to " . date('d-M-Y', $sunday) . "</P>";