PHP получить день с даты
$timestamp = strtotime('2009-10-22');
$day = date('D', $timestamp);
var_dump($day);
Lokesh003Coding
$timestamp = strtotime('2009-10-22');
$day = date('D', $timestamp);
var_dump($day);$today = date("d");
//Can Convert TO Int
print_r($today);// Prints the day
echo date("l") . "<br>";$datetime = DateTime::createFromFormat('YmdHi', '201308131830');
echo $datetime->format('D');
// or
$date = new \DateTime();
echo $date->format("D");
// This should get you a DateTime object from the date and year.
function getDateFromDay($dayOfYear, $year) {
$date = DateTime::createFromFormat('z Y', strval($dayOfYear) . ' ' . strval($year));
return $date;
}
// This should get you the day of the year and the year in a string.
date('z Y', strtotime('21 oct 2012'));