Получить параметры из строки URL в PHP
phpCopy<?php
echo $_GET['email'] . $_GET['name']
?>
CodeGuruDev
phpCopy<?php
echo $_GET['email'] . $_GET['name']
?>
phpCopy<?php
$url = "https://testurl.com/test/1234?email=abc@test.com&name=sarah";
$components = parse_url($url);
parse_str($components['query'], $results);
print_r($results);
?>
phpCopy<?php
$url = "https://testurl.com/test/1234?email=abc@test.com&name=sarah";
$components = parse_url($url);
parse_str($components['query'], $results);
echo($results['email']);
?>
phpCopy<?php
$url = "https://testurl.com/test/1234?email=abc@test.com&name=sarah";
$components = parse_url($url, PHP_URL_QUERY);
//$component parameter is PHP_URL_QUERY
parse_str($components, $results);
print_r($results);
?>