“Выберите SQL в PHP” Ответ

Выберите в php mysql

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}

$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
  // output data of each row
  while($row = $result->fetch_assoc()) {
    echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
  }
} else {
  echo "0 results";
}
$conn->close();
?>
  
  //aamirAlshawa
Jolly Jellyfish

запрос SQL в PHP

$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
    }
} else {
    echo "0 results";
}
$conn->close();
Terrible Toucan

Выберите SQL в PHP

<?php
$mysqli = new mysqli("localhost","my_user","my_password","my_db");

if ($mysqli -> connect_errno) {
  echo "Failed to connect to MySQL: " . $mysqli -> connect_error;
  exit();
}

$sql = "SELECT Lastname, Age FROM Persons ORDER BY Lastname";
$result = $mysqli -> query($sql);

// Associative array
$row = $result -> fetch_assoc();
printf ("%s (%s)\n", $row["Lastname"], $row["Age"]);

// Free result set
$result -> free_result();

$mysqli -> close();
?>
//eng.aamirAlshawa
Jolly Jellyfish

Выберите запрос в PHP

// objected oriented method
<?php
	$con=new mysqli("localhost","root","","dbname");
	$sql="select * from tbl";
	$res=$con->query($sql);
	
	$while($fetch=$res->fetch_object(){
      echo $fetch->uid;
      echo $fetch->uname;
      echo $fetch->unumber;
    }
  
?>
Temp Use

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