“function ()? Type {} в php” Ответ

function ()? Type {} в php

As of PHP 7.1.0, type declarations can be marked 
nullable by prefixing the type name with a question mark (?).
This signifies that the value can be of the specified type or null.

<?php
class C {}

function f(?C $c) {
    var_dump($c);
}

f(new C);
f(null);
?>