“DFS JavaScript” Ответ

DFS JavaScript

const dfs = (node) => { 
     stack.push(node);
     while (!stack.isEmpty()) {
        node = stack.pop();
        if (visited[node] == false) {
           visited[node] = true;
           console.log(`we visited ${node}`)
           for (let j = 0; j < graphAdj[node].length; j++) {
              if (graphAdj[node][j] === 1){
                  stack.push(j);
               }
            }
       }
     }
}