Получить ближайшее местоположение на основе широты и долготы JavaScript
function distance(lat1, lon1, lat2, lon2, unit) {
var radlat1 = Math.PI * lat1/180
var radlat2 = Math.PI * lat2/180
var theta = lon1-lon2
var radtheta = Math.PI * theta/180
var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
if (dist > 1) {
dist = 1;
}
dist = Math.acos(dist)
dist = dist * 180/Math.PI
dist = dist * 60 * 1.1515
if (unit=="K") { dist = dist * 1.609344 }
if (unit=="N") { dist = dist * 0.8684 }
return dist
}
var data = [{
"code": "0001",
"lat": "1.28210155945393",
"lng": "103.81722480263163",
"location": "Stop 1"
}, {
"code": "0003",
"lat": "1.2777380589964",
"lng": "103.83749709165197",
"location": "Stop 2"
}, {
"code": "0002",
"lat": "1.27832046633393",
"lng": "103.83762574759974",
"location": "Stop 3"
}];
var html = "";
var poslat = 1.28210155945393;
var poslng = 103.81722480263163;
for (var i = 0; i < data.length; i++) {
// if this location is within 0.1KM of the user, add it to the list
if (distance(poslat, poslng, data[i].lat, data[i].lng, "K") <= 0.1) {
html += '<p>' + data[i].location + ' - ' + data[i].code + '</p>';
}
}
$('#nearbystops').append(html);
Bloody Bear