“номер JavaScript к словам” Ответ

номер JavaScript к словам

var num = "zero one two three four five six seven eight nine ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen".split(" ");
var tens = "twenty thirty forty fifty sixty seventy eighty ninety".split(" ");

function number2words(n){
    if (n < 20) return num[n];
    var digit = n%10;
    if (n < 100) return tens[~~(n/10)-2] + (digit? "-" + num[digit]: "");
    if (n < 1000) return num[~~(n/100)] +" hundred" + (n%100 == 0? "": " and " + number2words(n%100));
    return number2words(~~(n/1000)) + " thousand" + (n%1000 != 0? " " + number2words(n%1000): "");
}
Darker

номер к слову JS

let a = [
  "",
  "one ",
  "two ",
  "three ",
  "four ",
  "five ",
  "six ",
  "seven ",
  "eight ",
  "nine ",
  "ten ",
  "eleven ",
  "twelve ",
  "thirteen ",
  "fourteen ",
  "fifteen ",
  "sixteen ",
  "seventeen ",
  "eighteen ",
  "nineteen ",
];
let b = [
  "",
  "",
  "twenty",
  "thirty",
  "forty",
  "fifty",
  "sixty",
  "seventy",
  "eighty",
  "ninety",
];

function inWords(num) {
  if ((num = num.toString()).length > 9) return "overflow";
  let n = ("000000000" + num)
    .substr(-9)
    .match(/^(\d{2})(\d{2})(\d{2})(\d{1})(\d{2})$/);
  if (!n) return;
  var str = "";
  str +=
    n[1] != 0
      ? (a[Number(n[1])] || b[n[1][0]] + " " + a[n[1][1]]) + "crore "
      : "";
  str +=
    n[2] != 0
      ? (a[Number(n[2])] || b[n[2][0]] + " " + a[n[2][1]]) + "lakh "
      : "";
  str +=
    n[3] != 0
      ? (a[Number(n[3])] || b[n[3][0]] + " " + a[n[3][1]]) + "thousand "
      : "";
  str +=
    n[4] != 0
      ? (a[Number(n[4])] || b[n[4][0]] + " " + a[n[4][1]]) + "hundred "
      : "";
  str +=
    n[5] != 0
      ? (str != "" ? "and " : "") +
        (a[Number(n[5])] || b[n[5][0]] + " " + a[n[5][1]]) +
        "only "
      : "";
  return str;
}

/* eslint eqeqeq: 0 */
sushangmi55

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