const names = ['John', 'Paul', 'George', 'Ringo', 'John'];
let unique = [...new Set(names)];
console.log(unique); // 'John', 'Paul', 'George', 'Ringo'let arr = [1,2,3,1,1,1,4,5]
let filtered = arr.filter((item,index) => arr.indexOf(item) === index)
console.log(filtered) // [1,2,3,4,5]array1 = array1.filter(function(val) {
return array2.indexOf(val) == -1;
});
// Or, with the availability of ES6:
array1 = array1.filter(val => !array2.includes(val));
// how to remove duplicates from array in javascript
// 1. filter()
let num = [1, 2, 3, 3, 4, 4, 5, 5, 6];
let filtered = num.filter((a, b) => num.indexOf(a) === b)
console.log(filtered);
// Result: [ 1, 2, 3, 4, 5, 6 ]
// 2. Set()
const removeDuplicates = (arr) => [...new Set(arr)];
console.log(removeDuplicates([1, 2, 3, 3, 4, 4, 5, 5, 6]));
// Result: [ 1, 2, 3, 4, 5, 6 ]const removeDuplicates = (arr) => [...new Set(arr)];
console.log(removeDuplicates([1, 2, 3, 3, 4, 4, 5, 5, 6]));
// Result: [ 1, 2, 3, 4, 5, 6 ]
const names = ["Alvi", "Arham", "Talha", "Safi", "Sameer", "Nazmi", "labli", "Arham", "Talha", "Labiba", "Tabassum", "Adiba"];
function removeDuplication(names) {
const unique = [];
for (element of names) {
if (unique.indexOf(element) == -1) {
unique.push(element)
}
}
return unique;
}
console.log(removeDuplication(names));
//Output:
/* [
'Alvi',
'Arham', 'Talha',
'Safi', 'Sameer',
'Nazmi', 'labli',
'Labiba', 'Tabassum',
'Adiba'
] */