Python добавить в список с индексом
list.insert(index, element)
Woolly Necked Stork
list.insert(index, element)thislist = ["apple", "banana", "cherry"]
thislist.insert(1, "orange")#add item to the beginning of list – at index 0
clouds = [‘Cisco’, ‘AWS’, ‘IBM’]
clouds.insert(0, ‘Google’)
print(clouds)
[‘Google’, ‘Cisco’, ‘AWS’, ‘IBM’]
#add item to the end of list
a.insert(len(a),x) is equivalent to a.append(x)
clouds = [‘Cisco’, ‘AWS’, ‘IBM’]
clouds.insert(len(clouds), ‘Google’)
print(clouds)
[‘Google’, ‘Cisco’, ‘AWS’, ‘IBM’]
#add item to specific index
number_list = [10, 20, 40] # Missing 30.
number_list.insert(2, 30 ) # At index 2 (third), insert 30.
print(number_list) # Prints [10, 20, 30, 40]
number_list.insert(100, 33)
print(number_list) # Prints [10, 20, 30, 40, 33]
number_list.insert(-100, 44)
print(number_list) # Prints [44, 10, 20, 30, 40, 33]# insert method places an element at an index you specify
foo = [1, 2, 3, 4]
foo.insert(1, 0.5)
print(foo)
# Output - [1, 0.5, 2, 3, 4]import sqlite3
# python data insert
conn = sqlite3.connect('TestDB.db')
name=input("enter your name \n ")
conutryID=int(input("enter your country id \n "))
sql = f''' INSERT INTO CLIENTS(Client_Name,Country_ID,Date)
VALUES('{name}',"{conutryID}","30/3/2022") '''
conn.execute(sql)
conn.commit()
conn.close()list_of_names = ["John", "Mike"]
print(list_of_names)
list_of_names.insert(0,"Amy") #insert Amy as the first item, at index 0
print(list_of_names)
list_of_names.insert(2,"Mario") #insert Mario as the third item, at index 2
print(list_of_names)
#['John', 'Mike']
#['Amy', 'John', 'Mike']
#['Amy', 'John', 'Mario', 'Mike']