Подсчет сортировки Java
import java.util.Arrays;
public class CountingSort {
/*
* This code performs a Counting sort of
* a list of positive integer values.
*
* Let n be size of the list to be sorted and
* m be the maximum value in the list
*
* Time complexity: O(n)
* Space complexity: O(n+m)
*
*/
public static void main(String[] args) {
int[] arr = { 2, 4, 3, 1 };
System.out.println(Arrays.toString(arr)); // [2, 4, 3, 1]
int[] sortedArr = countingSort(arr);
System.out.println(Arrays.toString(sortedArr)); // [1, 2, 3, 4]
}
private static int[] countingSort(int[] arr) {
/*
* The counting sort method counts the number
* of occurrences of every element in arr.
* Then uses that information to sort these elements.
*/
int max = findMax(arr);
if (max == Integer.MIN_VALUE) {
return new int[] {};
}
int[] counts = new int[max + 1];
for (int num : arr) {
counts[num]++;
}
for (int idx = 1; idx < counts.length; idx++) {
counts[idx] = counts[idx - 1] + counts[idx];
}
int[] sortedArray = new int[arr.length];
int current, sortedIdx;
for (int idx = arr.length - 1; idx >= 0; idx--) {
current = arr[idx];
counts[current]--;
sortedIdx = counts[current];
sortedArray[sortedIdx] = current;
}
return sortedArray;
}
private static int findMax(int[] arr) {
int max = Integer.MIN_VALUE;
for (int num : arr) {
if (num > max) {
max = num;
}
}
return max;
// or return Collections.max(Arrays.asList(arr));
}
}
Wissam