“Java jpa -критерий в xample” Ответ

Java jpa -критерий в xample

CriteriaQuery<DeptEmployee> criteriaQuery = 
  criteriaBuilder.createQuery(DeptEmployee.class);
Root<DeptEmployee> root = criteriaQuery.from(DeptEmployee.class);
In<String> inClause = criteriaBuilder.in(root.get("title"));
for (String title : titles) {
    inClause.value(title);
}
criteriaQuery.select(root).where(inClause);