“Результат корпуса магазина SQL” Ответ

Результат корпуса магазина SQL

declare
    @val int = 0;

select     
    @val = CASE 
        WHEN MONTH([DATE]) = MONTH(getdate()) AND
        YEAR([DATE]) = YEAR(getdate())
        THEN SUM(PROFIT)
        OVER (PARTITION BY [Name], 
            MONTH([DATE]), YEAR([DATE])) 
        ELSE 0 
        END 
FROM table_name
WHERE [Name] = @Name AND
      MONTH([DATE]) = @Month AND
      YEAR([DATE]) = @Year

print @val