FREQ COUNT в Python
freq = {}
for item in my_list:
if (item in freq):
freq[item] += 1
else:
freq[item] = 1
Amused Albatross
freq = {}
for item in my_list:
if (item in freq):
freq[item] += 1
else:
freq[item] = 1thislist = (1, 3, 7, 8, 7, 5, 4, 6, 8, 5)
x = thislist.count(5)
print(x)# list of cars
cars = ['Benz','BMW','Ford','Ferrari','volkswagen','BMW']
numbers= [1,5,2,5,7,1,3,3,1,6]
# BWM Count in list
bmwCount = cars.count('BMW')
print("total no BMW count is = ",bmwCount)
# number count in list
numCount = numbers.count(1)
print("The count of number 1 is = ",numCount)
# if you give number in string format
numCount = numbers.count('3')
print("The count of number 3 is= ",numCount)list_number = [6, 3, 8, 0]
length = len(list_number)
#output 4colors = ['red', 'green', 'blue', 'orange','blue']
color_count = colors.count('blue')
print('The count of color: blue is ', color_count)# create a list
numbers = [2, 3, 5, 2, 11, 2, 7]
# check the count of 2
count = numbers.count(2)
print('Count of 2:', count)
# Output: Count of 2: 3