Преобразовать список строк в Python Ints
test_list = ['1', '4', '3', '6', '7']
int_list = [int(i) for i in test_list]
EDestroyer
test_list = ['1', '4', '3', '6', '7']
int_list = [int(i) for i in test_list]>>> example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
>>> list(map(int, example_string.split(','))) # Python 3, in Python 2 the list() call is redundant
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
>>> [int(s) for s in example_string.split(',')]
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
[int(s) for s in example_string.split(',')]