Сортировать DataFrame по столбцу
df.sort_values(by='col1', ascending=False)
Magnificent Moth
df.sort_values(by='col1', ascending=False)df = df.reindex(sorted(df.columns), axis=1)
#old df columns
df.columns
Index(['A', 'B', 'C', 'D'],dtype='***')
#new column format that we want to rearange
new_col = ['D','C','B','A'] #list of column name in order that we want
df = df[new_col]
df.columns
Index(['D', 'C', 'B', 'A'],dtype='***')
#new column ordersorted = df.sort_values('column-to-sort-on', ascending=False)
#or
df.sort_values('name', inplace=True) final_df = df.sort_values(by=['2'], ascending=False)# Basic syntax:
import pandas as pd
df.sort_values(by=['col1'])
# Note, this does not sort in place unless you add inplace=True
# Note, add ascending=False if you want to sort in decreasing order
# Note, to sort by more than one column, add other column names to the
# list like by=['col1', 'col2']