word = input() if str(word) == str(word)[::-1] : print("Palindrome") else: print("Not Palindrome")p = list(input())
for i in range(len(p)):
if p[i] == p[len(p)-1-i]:
continue
else:
print("NOT PALINDROME")
break
else:
print("PALINDROME")"""
This implementation checks whether a given
string is a palindrome. A string is
considered to be a palindrome if it reads the
same forward and backward. For example, "kayak"
is a palindrome, while, "door" is not.
Let n be the length of the string
Time complexity: O(n),
Space complexity: O(1)
"""
def isPalindrome(string):
# Maintain left and right pointers
leftIdx = 0
rightIdx = len(string)-1
while leftIdx < rightIdx:
# If chars on either end don't match
# string cannot be a palindrome
if string[leftIdx] != string[rightIdx]:
return False
# Otherwise, proceed to next chars
leftIdx += 1
rightIdx -= 1
return True
print(isPalindrome("kayak")) # True
print(isPalindrome("door")) # False
a=input('enter a string :')# palindrome in string
b=a[::-1]
if a==b:
print(a,'is a palindrome')
else:
print(a,'is not a palindrome')
print('a is not equal to b')
if a!=b:
print(b, 'the reverse of', a)
#output:
--------------------------------------------------------------------------------
case-I
# not palindrome
enter a string :1254
1254 is not a palindrome
a is not equal to b
4521 the reverse of 1254
--------------------------------------------------------------------------------
case-II
# palindrme
enter a string :12321
12321 is a palindromedef palindrome(a):
return a == a[::-1]
palindrome('radar') # Truen = input("Enter the word and see if it is palindrome: ") #check palindrome
if n == n[::-1]:
print("This word is palindrome")
else:
print("This word is not palindrome")
print("franco")