“функция getLine в c” Ответ

getLine () в c

#include <stdlib.h>
#include <stdio.h>  


#define FILENAME "example.txt"

int main(void)
{
  /* Open the file for reading */
  char *line_buf = NULL;
  size_t line_buf_size = 0;
  int line_count = 0;
  ssize_t line_size;
  FILE *fp = fopen(FILENAME, "r");
  if (!fp)
  {
    fprintf(stderr, "Error opening file '%s'\n", FILENAME);
    return EXIT_FAILURE;
  }

  /* Get the first line of the file. */
  line_size = getline(&line_buf, &line_buf_size, fp);

  /* Loop through until we are done with the file. */
  while (line_size >= 0)
  {
    /* Increment our line count */
    line_count++;

    /* Show the line details */
    printf("line[%06d]: chars=%06zd, buf size=%06zu, contents: %s", line_count,
        line_size, line_buf_size, line_buf);

    /* Get the next line */
    line_size = getline(&line_buf, &line_buf_size, fp);
  }

  /* Free the allocated line buffer */
  free(line_buf);
  line_buf = NULL;

  /* Close the file now that we are done with it */
  fclose(fp);

  return EXIT_SUCCESS;
}
Defeated Dingo

функция getLine в c

#include <stdio.h>

int main()
{
  int bytes_read;
  int nbytes = 100;
  char *my_string;

  puts ("Please enter a line of text.");

  /* These 2 lines are the heart of the program. */
  my_string = (char *) malloc (nbytes + 1);
  bytes_read = getline (&my_string, &nbytes, stdin);

  if (bytes_read == -1)
    {
      puts ("ERROR!");
    }
  else
    {
      puts ("You typed:");
      puts (my_string);
    }

  return 0;
}
Proud Penguin

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