Распечатайте количество раз, когда подстроение происходит в данной строке
nStr = '000123000123'
pattern = '123'
count = 0
flag = True
start = 0
while flag:
a = nStr.find(pattern, start) # find() returns -1 if the word is not found,
#start i the starting index from the search starts(default value is 0)
if a == -1: #if pattern not found set flag to False
flag = False
else: # if word is found increase count and set starting index to a+1
count += 1
start = a + 1
print(count)
android developer