“Python Run Docker Integrading Subprocess” Ответ

Python Run Docker Integrading Subprocess

run_this = "print('hi')"
random_name = ''.join(random.SystemRandom().choice(string.ascii_uppercase + string.digits) for _ in range(20))
command = 'docker run -i -t --name="%s" dockerfile/python /bin/bash' % random_name
subprocess.call([command],shell=True,stderr=subprocess.STDOUT)
command = 'cat <<\'PYSTUFF\' | timeout 0.5 python | head -n 500000 \n%s\nPYSTUFF' % run_this
output = subprocess.check_output([command],shell=True,stderr=subprocess.STDOUT)
command = 'exit'
subprocess.call([command],shell=True,stderr=subprocess.STDOUT)
command = 'docker ps -a | grep "%s" | awk "{print $1}" | xargs --no-run-if-empty docker rm -f' % random_name
subprocess.call([command],shell=True,stderr=subprocess.STDOUT)
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Python Run Docker Integrading Subprocess

from subprocess import Popen, PIPE

p = Popen("docker run -i -t --name="%s" dockerfile/python /bin/bash", stdin=PIPE)
p.communicate("timeout 0.5 python | head -n 500000 \n" % run_this)
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Docker Python Run Subprocess Python Run Docker Интерактивно подпроцесс

import os
os.system('docker run -it --rm ubuntu bash')
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Docker Python Run Subprocess Python Run Docker Интерактивно подпроцесс

import pty
import sys
import select
import os
import subprocess

pty, tty = pty.openpty()

p = subprocess.Popen(['docker', 'run', '-it', '--rm', 'ubuntu', 'bash'], stdin=tty, stdout=tty, stderr=tty)

while p.poll() is None:
    # Watch two files, STDIN of your Python process and the pseudo terminal
    r, _, _ = select.select([sys.stdin, pty], [], [])
    if sys.stdin in r:
        input_from_your_terminal = os.read(sys.stdin.fileno(), 10240)
        os.write(pty, input_from_your_terminal)
    elif pty in r:
        output_from_docker = os.read(pty, 10240)
        os.write(sys.stdout.fileno(), output_from_docker)
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