Python регулярно выражение
from django.urls import path, re_path
from . import views
urlpatterns = [
path('articles/2003/', views.special_case_2003),
re_path(r'^articles/(?P<year>[0-9]{4})/$', views.year_archive),
re_path(r'^articles/(?P<year>[0-9]{4})/(?P<month>[0-9]{2})/$', views.month_archive),
re_path(r'^articles/(?P<year>[0-9]{4})/(?P<month>[0-9]{2})/(?P<slug>[\w-]+)/$', views.article_detail),
]
Sanvi Rahman