Python получить текущее местоположение файла
import os
os.path.dirname(os.path.abspath(__file__))
Proud Polecat
import os
os.path.dirname(os.path.abspath(__file__))# Option 1: Works for Python 3.4 +
from pathlib import Path
Path(__file__).name # ScriptName.py
Path(__file__).stem # ScriptName
# Option 2: use `os` library
import os
os.path.basename(__file__) # ScriptName.py
os.path.splitext(os.path.basename(__file__))[0] # ScriptNameimport os
os.path.basename(__file__)from pathlib import Path
print(Path(__file__).stem) #myfile
print(Path(__file__).name) #myfile.pyimport os
os.path.basename(__file__)Use __file__. If you want to omit the directory part (which might be present), you can use os.path.basename(__file__)