Перезагрузка функции представления Django с сбросом контекстных данных

//parent_template.html
{% load static %}
<script src="{% static "jquery.js" %}"></script>

{% block first %}
<div class="row">
    {% for x in my_list %}
    <button class="some-filter" id="{{x}}"></button>
    {% endfor %}
</div>
{% endblock first %}

{% block second %}
<div class="row" id="some_id"></div>
{% endblock second %}

<script>
     $(".some-filter").on({
       click: e=> {
           var name = $( e.target )[0].id;
           $.ajax({
             url: '/ajax/info_getter/',
             data: {
               'name': name,
             },
             dataType: 'html',
             success: function (data) {
               if (data) {
                 $("#some_id").html(data);
                 $(".some-filter").removeClass('selected');
                 $( e.target ).addClass('selected');
               }
             }
           });
       }
   })
</script>



// child_template.html
// my big ass template containing lots of image files
{% load static %}
...other stuff

// urls.py
from django.urls import path
from . import views
urlpatterns = [
    ...
    path('ajax/info_getter/', views.info_getter, name='info_getter'),
    ...
]



// views.py
from django.shortcuts import render
...
def info_getter(request):
    name = request.GET.get('name', None)
    if name:
        context["name"] = name

    response = render(request, "child_template.html", context=context)
    return response
Jittery Jackal