“ПАФРАЗЕР онлайн” Ответ

ПАФРАЗЕР онлайн

ef calc_time(speed, distance):
    return distance / speed


def extra_search(node, start, destination, trav_paths, travelled):
    paths = trav_paths[node] #Get possible starts from new starting city
    route = travelled.copy() #Get a copy of the previous travelled path from the source
    
    travel = []
    for i in range(len(paths)):
        if paths[i][1] == start: 
            continue
        elif paths[i][1] == destination: 
            route.append(paths[i][1])
        else:
            if paths[i][1] not in route: 
                route.append(paths[i][1])
                route = extra_search(paths[i][1], start, destination, trav_paths, route)
            else:
                continue
Blue Beetle

ПАФРАЗЕР онлайн

def singkatankata(p, s):
    ret = ""
    jumlah = 0
    for i in range(p):
        if i == 0 or s[i] != s[i-1]:
            ret += s[i]
            jumlah = 1
        if s[i] == s[i-1]:
            jumlah += 1
        if i == p-1 or s[i] != s[i+1]:
            ret += str(jumlah)
    return ret


for i in range(int(input("Masukkan banyak kata: "))):
    
    jawab = singkatankata(int(input(f"Masukkan panjang kata ke-{i+1}: ")), input(f"Masukkan kata ke-{i+1}: "))
    print(f"Singkatan kata ke-{i+1}: {jawab}")
Old-fashioned Ocelot

ПАФРАЗЕР онлайн

clc;
vol = 30:10:70; betal = 50:10:60; g = 9.81;
rho = @(t) vo.^2*(cos(beta)).^2*sqrt((1+(-g*t./(vo.*cos(beta)) + tan(beta)).^2).^3)./g;
for i = 1:length(vol)
    for j = 1:length(betal)
        vo = vol(i);
        beta = betal(j);
        fplot(rho,[2*vo*sin(beta)/g, 0], 'DisplayName', strcat('vo = ',num2str(vo),' beta =', num2str(beta)))
        hold on
    end
end
Rich Rhinoceros

ПАФРАЗЕР онлайн

  fplot(deta,[2*v0*sin(Bo)/g, 0], 'DisplayName', strcat('v0 = ',num2str(v0),' Bo =', num2str(Bo)))
        hold on
Rich Rhinoceros

ПАФРАЗЕР онлайн

#1
inputstr1=input('Enter elements separated by ,(comma) for set1:')
inputstr2=input('Enter elements separated by ,(comma) for set2:')
inputt1=inputstr1.split(',')
inputt2=inputstr2.split(',')
inset1=set(inputt1)
inset2=set(inputt2)
print('Symmetric_difference of set1 and set2:',list(inset1.symmetric_difference(inset2)))
print('set1 ^ set2:',list(inset1^inset2))
inset1.symmetric_difference_update(inset2)
print('Sorted order of set1 after symmetric_difference_update:',sorted(list(inset1)))
print('Sorted order of set2 after symmetric_difference_update:',sorted(list(inset2)))
inputstr3=input('Enter elements separated by ,(comma) for set3:')
inputstr4=input('Enter elements separated by ,(comma) for set4:')
inputt3=inputstr3.split(',')
inputt4=inputstr4.split(',')
inset3=set(inputt3)
inset4=set(inputt4)
inset3^=inset4
print('Sorted order of set3 after (set3 ^= set4):',sorted(list(inset3)))
print('Sorted order of set4 after (set3 ^= set4):’,sorted(list(inset4)))
Weerapol Paengya

ПАФРАЗЕР онлайн

clc;
vol = 30:10:70; betal = 50:10:60; g = 9.81;
rho = @(t) vo.^2*(cos(beta)).^2*sqrt((1+(-g*t./(vo.*cos(beta)) + tan(beta)).^2).^3)./g;
for i = 1:length(vol)
    for j = 1:length(betal)
        vo = vol(i);
        beta = betal(j);
        fplot(rho,[2*vo*sin(beta)/g, 0], 'DisplayName', strcat('vo = ',num2str(vo),' beta =', num2str(beta)))
        hold on
    end
end
Rich Rhinoceros

ПАФРАЗЕР онлайн

clc;
syms t vo beta g
rho = vo.^2*(cos(beta)).^2*sqrt((1+(-g*t./(vo.*cos(beta)) + tan(beta)).^2).^3)./g

theta = atan(-g*t/(vo*cos(beta)) + tan(beta));
vel = rho*diff(theta,t);
at = diff(vel,t)
an = vel^2/rho

at = matlabFunction(at);
an = matlabFunction(an);
clf;
vol = 30:10:70; betal = 50:10:60; g = 9.81;
for i = 1:length(vol)
    for j = 1:length(betal)
        vo = vol(i);
        beta = betal(j);
        fplot(at(beta,g,t,vo),[2*vo*sin(beta)/g, 0], 'DisplayName', strcat('v0 = ',num2str(vo),' beta =', num2str(beta)))
        hold on
    end
end
xlabel("t"); ylabel("a_t"); legend("show")
Rich Rhinoceros

ПАФРАЗЕР онлайн

#include <stdio.h>
int main() {
   int year;
   printf("Enter a year: ");
   scanf("%d", &year);

   // leap year if perfectly divisible by 400
   if (year % 400 == 0) {
      printf("%d is a leap year.", year);
   }
   // not a leap year if divisible by 100
   // but not divisible by 400
   else if (year % 100 == 0) {
      printf("%d is not a leap year.", year);
   }
   // leap year if not divisible by 100
   // but divisible by 4
   else if (year % 4 == 0) {
      printf("%d is a leap year.", year);
   }
   // all other years are not leap years
   else {
      printf("%d is not a leap year.", year);
   }

   return 0;
}
Defeated Donkey

Ответы похожие на “ПАФРАЗЕР онлайн”

Вопросы похожие на “ПАФРАЗЕР онлайн”

Смотреть популярные ответы по языку

Смотреть другие языки программирования

Shell/Bash
C#
C++
C
CSS
HTML
Java
JavaScript
Objective-C
PHP
Python
Sql
Swift
Ruby
TypeScript
Go
Kotlin
Assembly
R
VBA
Scala
Rust
Dart
Elixir
Clojure
Haskell
Matlab
Erlang
Cobol
Fortran
Scheme
Perl
Groovy
Lua
Julia
Delphi
Abap
Lisp
Prolog
Pascal
ActionScript
Basic
Solidity
PowerShell
GDScript
Excel