“нечетный или даже питон” Ответ

Как найти, если значение равно или странно в Python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")
Da Skeptical

Программа, чтобы найти четные цифры в Python

m = int(input("Enter number"))
if m % 2 == 0:
    print(m,"is an even number")
else:
    print(m,"is an odd number")

    
Upset Unicorn

Как проверить, является ли номер нечетный питон

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))  
Some Random Programmer

Странно или даже в питоне

n = int(input("Enter a number: "))
print(n,"is Even.") if (n % 2) == 0 else print(n,"is Odd.")
moghaazi

нечетный или даже питон

num = int(input("Number: "))
mod = num % 2
if mod == 0:
    print(f"{num} is even")
else:
    print(f"{num} is odd")
Obnoxious Opossum

Нечетный или даже питон

#! /urs/bin/env python3

# odd_or_even_function: this function will take in one integer parameter
# returning: print statements to console to inform user if the numbered entered
# was an even, odd, or divisible by 4.
def odd_or_even_function(num, check):

    # Calculating when num will be even but not divisible by 4
    if int(num) % 2 == 0 and int(num) % 4 != 0:
        print("The number " + str(num) + " is an even number")

    # Calculating when num will be divisible by 4
    elif int(num) % 2 == 0 and int(num) % 4 == 0:
        print("The number " + str(num) + " is an number divisible by 4.")

    # Calculating when num will be odd
    else:
        print("The number " + str(num) + " is an odd number")

    # Calculating when num can or can't divide evenly into check
    if int(num) % int(check) == 0:
        print(str(num) + " divides evenly by " + str(check))
    else:
        print(str(num) + " does not divide evenly by " + str(check))


def main():
    # information msg
    print("enter 'exit' to end program")
    print()

    # user_num = 1 so that we
    # can force user_num to enter while loop
    user_num = 1

    # user will be prompted to enter a number
    # this program will run until the user enters 'x'
    # then that will trigger the while loop
    # and program to close
    user_num = input("Enter a number: ")
    user_check = input("Enter a check number: ")
    while user_num != 'exit':
        odd_or_even_function(user_num, user_check)
        print()
        user_num = input("Enter a number: ")

    print("¡Hasta luego amigo!")


if __name__ == "__main__":
    main()
Weary Warbler

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