конвертировать номер в Word JS
let a = [
"",
"one ",
"two ",
"three ",
"four ",
"five ",
"six ",
"seven ",
"eight ",
"nine ",
"ten ",
"eleven ",
"twelve ",
"thirteen ",
"fourteen ",
"fifteen ",
"sixteen ",
"seventeen ",
"eighteen ",
"nineteen ",
];
let b = [
"",
"",
"twenty",
"thirty",
"forty",
"fifty",
"sixty",
"seventy",
"eighty",
"ninety",
];
function inWords(num) {
if ((num = num.toString()).length > 9) return "overflow";
let n = ("000000000" + num)
.substr(-9)
.match(/^(\d{2})(\d{2})(\d{2})(\d{1})(\d{2})$/);
if (!n) return;
var str = "";
str +=
n[1] != 0
? (a[Number(n[1])] || b[n[1][0]] + " " + a[n[1][1]]) + "crore "
: "";
str +=
n[2] != 0
? (a[Number(n[2])] || b[n[2][0]] + " " + a[n[2][1]]) + "lakh "
: "";
str +=
n[3] != 0
? (a[Number(n[3])] || b[n[3][0]] + " " + a[n[3][1]]) + "thousand "
: "";
str +=
n[4] != 0
? (a[Number(n[4])] || b[n[4][0]] + " " + a[n[4][1]]) + "hundred "
: "";
str +=
n[5] != 0
? (str != "" ? "and " : "") +
(a[Number(n[5])] || b[n[5][0]] + " " + a[n[5][1]]) +
"only "
: "";
return str;
}
/* eslint eqeqeq: 0 */
sushangmi55