“Альтернативная капитализация” Ответ

Альтернативная капитализация

// Given a string, capitalize the letters that occupy even indexes and odd indexes separately, and return as shown below. Index 0 will be considered even.
// For example, capitalize("abcdef") = ['AbCdEf', 'aBcDeF']. See test cases for more examples.
// The input will be a lowercase string with no spaces.

const capitalize = s => {
  s = s.split('')
  let finalArr = []
  let i = 0
  while(i < 2){
    let str = ''
    s.forEach((letter, index) => {
      if(i % 2 === 0 && index % 2 === 0) str += letter.toUpperCase()
      else if(i % 2 !== 0 && index % 2 !== 0) str += letter.toUpperCase()
      else str += letter
    } )
    
    finalArr.push(str)
    i++
  }
  return finalArr
};
console.log(capitalize("abcdef"))

// With love @kouqhar