инициализировать массив в C
int nums[100] = {0}; // initiallize all values to 0
int nums[5] = {1,2,3,4,5};
// type name[size] = {values};
sachin_duhan
int nums[100] = {0}; // initiallize all values to 0
int nums[5] = {1,2,3,4,5};
// type name[size] = {values};
e = ((a < d) ? (a++) : (a = d))
//advance if else condition
You can use '#' sign to get exact name of an argument passed to a macro:
#define what_is(x) cerr << #x << " is " << x << endl;
int variable = 376;
what_is(variable);
// prints "variable is 376"