Номер 10
#include <stdio.h>
int main()
{
int a = 30;
int b = 10;
int c = 15;
int d = 5;
int e;
e = (a + b) * c / d;
// ( 30 * 15 ) / 5
printf("Value of (a + b) * c / d is : %d\n", e );
e = ((a + b) * c) / d;
// (30 * 15 ) / 5
printf("Value of ((a + b) * c) / d is : %d\n" , e );
e = (a + b) * (c / d);
// (30) * (15/5)
printf("Value of (a + b) * (c / d) is : %d\n", e );
e = a + (b * c) / d;
// 30 + (150/5)
printf("Value of a + (b * c) / d is : %d\n" , e );
return 0;
}
Marlon Oquina