Аргументы командной строки c
int main(int argc, char* argv[]){/*...*/}
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int main(int argc, char* argv[]){/*...*/}#include <stdio.h>
int main(int argc, char **argv) {
for (int i = 0; i < argc; ++i) {
printf("argv[%d]: %s\n", i, argv[i]);
}
}
/*
[birryree@lilun c_code]$ ./a.out hello there
argv[0]: ./a.out
argv[1]: hello
argv[2]: there
*/You can use as your main function:
int main(int argc, char **argv)
So, if you entered to run your program:
C:\myprogram myfile.txt
argc will be 2
argv[0] will be myprogram
argv[1] will be myfile.txt
To read the file:
FILE *f = fopen(argv[1], "r");